Converting fifth roots from polar form to complex

[Braka]

Homework Statement

I am looking for the fifth roots of unity, which I believe come in the form of:

cos(2kpi/5) + isin(2kpi/5), k=1,2,3,4,5 and when k=5, the complex number is 1.

how do you convert the rest to complex numbers? Normally, I use common triangles like:

45-45-90 and 30-60-90

but I don't think there is a triangle for 2pi/5.

Homework Equations

The Attempt at a Solution

 

[e(ho0n3]

I don't understand your question. cos(2kpi/5) + isin(2kpi/5) is a complex number. Do you want to convert that into polar form? It should be pretty obvious.

 

[Braka]

Its obvious? I can't recall how to get it. What I meant is I wanted to put it in a +bi form. That is my problem. Sorry for stating it in a confusing manner

 

[rock.freak667]

It is already in the form a+bi.
a=cos(2kpi/5)
b=sin(2kpi/5)