- #1
iloveannaw
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Homework Statement
Hi, we're supposed to put the following integral into a power series:
[tex]\int \frac{arctan(t)}{t} dt [/tex]
with 0 < t < x.
Homework Equations
n/a
The Attempt at a Solution
I just want to know whether this step is ok.
[tex]\int \frac{arctan(t)}{t} dt = \int \frac{1}{t} \int \frac{dy}{1-(-y^2)} dt [/tex]
with 0 < y < t and 0 < t < x
Happy Easter!
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