Converting Integral into Power Series: Is This Step Valid?

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iloveannaw
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Homework Statement



Hi, we're supposed to put the following integral into a power series:

[tex]\int \frac{arctan(t)}{t} dt[/tex]

with 0 < t < x.

Homework Equations



n/a

The Attempt at a Solution



I just want to know whether this step is ok.

[tex]\int \frac{arctan(t)}{t} dt = \int \frac{1}{t} \int \frac{dy}{1-(-y^2)} dt[/tex]

with 0 < y < t and 0 < t < x

Happy Easter!
 
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I agree with it.