Converting logic diagram to only NAND gates

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A NAND gate can function as an inverter when both of its inputs are tied together, allowing it to output the NOT of the input signal. This configuration results in the NAND truth table producing outputs of 1 for both inputs being 0 and 0 for both inputs being 1. Alternatively, connecting one input of the NAND gate to a constant logic 1 also enables it to act as an inverter. The discussion emphasizes the versatility of NAND gates in digital logic design. Understanding these configurations is crucial for simplifying logic diagrams using only NAND gates.
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Homework Statement



How is he able to just swap the inverter for a NAND gate? Doesn't a NAND gate require two things?

See the text on the right for his explanation
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Homework Equations

The Attempt at a Solution

 
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LongApple said:
How is he able to just swap the inverter for a NAND gate? Doesn't a NAND gate require two things?
What sort of "things" did you have in mind? If the inputs are tied together then the only inputs available to the NAND are both inputs "1" or both inputs "0". What does a NAND gate output for each case?
 
LongApple said:
How is he able to just swap the inverter for a NAND gate?
So, we are revisiting this topic! :) We thought you would learn about the NAND inverter from your previous thread, but I think you dropped out and didn't see it through to its conclusion.

You can join the two inputs together, which gives both inputs either 1 or both inputs 0, and the output becomes the NOT of this. So, yes, a NAND gate with a signal applied to both its inputs acts as a NOT gate.
 
Or look at it this way.. The NAND truth table is

00=1
01=1
10=1
11=0

if both inputs are wired together they are always the same, so the only combinations that can occur are..

00=1
11=0

There is another way to turn a NAND gate into an inverter - You could just connect one input to a logic 1 permanently...

10=1
11=0
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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