Converting stress-strain curve to shear stress-shear strain

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SUMMARY

This discussion focuses on converting a stress-strain curve from a monotonic uniaxial tension test of crystalline metal materials into a corresponding pure shear stress-shear strain curve. Key equations include the elastic modulus (E), Poisson ratio (v), and shear modulus (G = E/[2*(1+v)]). The conversion of normal stresses to shear stresses utilizes the τ_crss equation, while elastic shear strains are derived from τ/G. The challenge lies in determining the plastic shear strains, particularly in the plastic region, where the relationship is governed by von Mises plasticity, yielding a shear stress of τ = σ_y/√3.

PREREQUISITES
  • Understanding of elastic and plastic deformation in materials
  • Familiarity with stress-strain relationships and material properties
  • Knowledge of the von Mises yield criterion
  • Proficiency in using equations related to shear modulus and stress conversion
NEXT STEPS
  • Study the application of the τ_crss equation for shear stress conversion
  • Learn about the implications of von Mises plasticity in material behavior
  • Research methods for determining plastic shear strains in metals
  • Explore graphical representation techniques for stress-strain curves
USEFUL FOR

Materials scientists, mechanical engineers, and students studying material mechanics who are interested in understanding the behavior of crystalline metals under stress and strain conditions.

turpy
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Homework Statement


For a crystalline metal material
- Elastic modulus E
- Poisson ratio v
- A table with test data of stresses vs. total strains, from a monotonic uniaxial tension test, which generates a stress-strain curve.

How would you use this data to find the corresponding pure shear stress-strain curve?

Homework Equations


ε_elastic = (σ/E)
γ_elastic = (τ/G)
G=E/[2*(1+v)]

The Attempt at a Solution


Using the crystal structure of metal, the normal stresses from the table could be converted to shear stresses via the τ_crss equation (http://virtualexplorer.com.au/special/meansvolume/contribs/wilson/Critical.html )

Then, the elastic shear strains can be obtained from τ/G. But what about the plastic shear strains? This is where I'm stuck. Hints/help would be highly appreciated!
 
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turpy said:

Homework Statement


For a crystalline metal material
- Elastic modulus E
- Poisson ratio v
- A table with test data of stresses vs. total strains, from a monotonic uniaxial tension test, which generates a stress-strain curve.

How would you use this data to find the corresponding pure shear stress-strain curve?

Homework Equations


ε_elastic = (σ/E)
γ_elastic = (τ/G)
G=E/[2*(1+v)]

The Attempt at a Solution


Using the crystal structure of metal, the normal stresses from the table could be converted to shear stresses via the τ_crss equation (http://virtualexplorer.com.au/special/meansvolume/contribs/wilson/Critical.html )

Then, the elastic shear strains can be obtained from τ/G. But what about the plastic shear strains? This is where I'm stuck. Hints/help would be highly appreciated!
You use the tensile test to determine the Young's modulus and the poisson ratio. Then you use your equation to calculate the shear modulus G from these. Then you plot shear stress vs shear strain with a slope of G.

Chet
 
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Hi Chet,
Thanks for the response. That covers the linear elastic region of the shear stress-shear strain curve, but what about the plastic region?
 
turpy said:
Hi Chet,
Thanks for the response. That covers the linear elastic region of the shear stress-shear strain curve, but what about the plastic region?
I don't have the answer to this immediately up my sleeve. I want to spend a little time playing with the equations.

Chet
 
Chestermiller said:
I don't have the answer to this immediately up my sleeve. I want to spend a little time playing with the equations.

Chet
If there is a way of doing it in the plastic region, I have not been able to figure out how. It certainly can't be done directly from the experimental measurements because, for all possible plane orientations within the sample, with this kind of uniaxial loading, there is no orientation in which there is a pure shear stress on the plane. There is always a normal component of the stress (except, of course, at 90 degrees to the load, where the shear stress is zero).

Chet
 
In the same way that 3D elasticity tells you G, based on E and \nu, plasticity (von Mises) tells you that the material will "yield" in pure shear at a value of \tau_y, which is known, based on your known uniaxial yield stress, \sigma_y. This value is:
\tau=\frac{\sigma_y}{\sqrt{3}}

Again, the assumption there is von Mises plasticity.

Hope that helps
 
Last edited:

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