Converting to Cartesian Form in Polar Coordinates

  • Thread starter Thread starter thomas49th
  • Start date Start date
  • Tags Tags
    Polar
Click For Summary
Converting polar coordinates to Cartesian form is not necessary for this problem, as it can be effectively solved using polar coordinates. The discussion emphasizes that the problem is well-suited for polar methods, suggesting that maintaining the original form is advantageous. There is no need to use tangent or other Cartesian-related functions in this case. The consensus is to solve the problem directly in polar coordinates for optimal results. This approach simplifies the solution process and avoids unnecessary conversions.
thomas49th
Messages
645
Reaction score
0

Homework Statement



Maths001.jpg


Homework Equations


The Attempt at a Solution



Should I convert it all to a Cartesian form?
Will I be using tan somewhere along the way?

Thanks
 
Physics news on Phys.org
thomas49th said:
Should I convert it all to a Cartesian form?

Nooo :frown: … leave it as it is …

it's a perfect problem for solving in polar coordinates. :wink:
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 24 ·
Replies
24
Views
3K
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
16
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K