Converting Transmission to Absorbance (Optics)

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To convert transmission data to absorbance for different thicknesses of glass, the equation A = 2 - Log(T%) is a starting point, but it does not account for thickness. The conservation of energy equation (a + t + r = 1) indicates that if reflection (r) is negligible, then absorption (a) equals 1 minus transmission (t). Beer's law, which applies to weakly scattering materials, relates absorbance to thickness through the formula I = I_0 * 10^(-al), where 'a' is the absorption coefficient and 'l' is the thickness. Understanding these relationships will help in generalizing transmission data across varying glass thicknesses. Utilizing resources like the Wikipedia page on Beer’s law can provide further guidance on this topic.
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I have taken data for the transmission vs. wavelength for several types of glasses in the IR. I want to convert this to absorbance so that I can generalize transmission to different thickness glasses.

I found an equation online that stated A = 2-Log(T%) (where Log is base 10). But I do not see how this considers thickness.

Does anyone know how I can translate knowing the transmission % for a specific thickness glass to knowing the absorbance/transmission to thicker glasses?
 
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There's a few simple formulas you can use. Starting with conservation of energy, a+t+r = 1, where 'a' is the fraction of absorbed light, 'r' the fraction of reflected light, and 't' the fraction of transmitted light.

If r = 0 (or the measurements are performed in such a way to allow r = 0), then a = 1-t. As you note, this can often be written in a way that accounts for a material's thickness. Beer's law is an approximation valid for 'weakly scattering' materials, and is given as:

I = I_0 *10^(-al), where 'a' is the *absorption coefficient* (not the same 'a' as above), and 'l' the thickness. ('t' = I/I_0)

http://en.wikipedia.org/wiki/Beer's_law

Now, you have the transmission as a percentage, but hopefully the wiki page will guide you along at this point.
 
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