How do I convolve delta functions in Fourier transform calculations?

AI Thread Summary
To find the Fourier transform of Cos(10t)sin(t), it is suggested to simplify the expression using half sum difference identities, resulting in 1/2 (sin(11t) - sin(9t). This approach makes the convolution of delta functions more straightforward, as it involves adding frequency shifts rather than direct convolution. The discussion emphasizes that simplifying the trigonometric expression can significantly ease the calculation process. Overall, this method proves to be an effective strategy for handling such Fourier transform problems.
jackdaniel
Messages
2
Reaction score
0
Hi everyone, I need help finding the Fourier transform of Cos(10t)sin(t)

i know that i need to find the transform of cos and sin and then convolve them, but i m not sure how to convolve delta function. I would really appreciate any helps.
 
Mathematics news on Phys.org
No it's better to do it by simplifying the trig expression first using the "half sum difference" identities.

That is, cos(10t)sin(t) = 1/2 ( sin(11t) - sin(9t) )
 
thanks, the way you described made it a lot easier. By using your method I realized that convolving delta functions is simply adding the frequency shifts.

thanks
 
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...
Back
Top