Cooling of water vapor - air mixture to T < 273K

AI Thread Summary
Cooling a mixture of water vapor and air to temperatures below 273 K can lead to complex phase equilibria. At temperatures above 273 K, water typically exists in gaseous and liquid states simultaneously, but below this threshold, solid water (ice) can also form. The saturation pressure of water vapor remains above zero, indicating that some vapor can coexist with solid ice. This suggests that a gas/solid equilibrium is possible, allowing for the presence of both phases in the mixture. Understanding these dynamics is crucial for applications in meteorology and climate science.
mike133
Messages
10
Reaction score
0
What happens if you cool the mixture of water vapor and air to the temperature lower than 273 K? Since saturation pressure is higher than 0 some vapor should stay in the air. In the solid form?
 
Physics news on Phys.org
Welcome to PF.

At 280K, water can (and usually does on Earth!) simultanously exist in gaseous and liquid states, in equilibrium. No reason why you can't have a gas/solid equilibrium too.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...

Similar threads

Replies
13
Views
4K
Replies
5
Views
3K
Replies
30
Views
6K
Replies
1
Views
3K
Replies
9
Views
3K
Replies
3
Views
1K
Replies
2
Views
13K
Replies
1
Views
10K
Back
Top