- #1
hjel0743
- 5
- 0
Can someone help me with the conversion of this equation to Cartesian coordinates:
2cosθr + sinθθ
(Due to formatting limitations, I just made the r_hat and theta_hat components bold-faced)
I know the answer ought to be -(3y2)/[(x2+y2)+1] but I've tried every variation of the 3 main coordinate transformation eqns that I can think of and haven't gotten anywhere. Those 3 eqns I'm talking about are y=rsinθ, x=rcosθ, and r=sqrt(x2+y2).
Any help would be great. (Not homework related, need to get this for some research I'm working on.)
2cosθr + sinθθ
(Due to formatting limitations, I just made the r_hat and theta_hat components bold-faced)
I know the answer ought to be -(3y2)/[(x2+y2)+1] but I've tried every variation of the 3 main coordinate transformation eqns that I can think of and haven't gotten anywhere. Those 3 eqns I'm talking about are y=rsinθ, x=rcosθ, and r=sqrt(x2+y2).
Any help would be great. (Not homework related, need to get this for some research I'm working on.)