Undergrad Coordinate systems parameterized by pseudo arc-length

Click For Summary
A coordinate system for a circular arc making a specified angle α with a 90-degree wedge is discussed, focusing on parametrization. The example provided uses α = π/2, resulting in a quarter circle represented by the vector T = (sin s, cos s) for s in the range [0, π/2]. The conversation emphasizes the distinction between defining a coordinate system and searching for a parametrization. The discussion also raises the challenge of adjusting the parametrization for angles other than 90 degrees, suggesting that the center of the circle could move along the line y = x. Trigonometric calculations are necessary to determine the appropriate domain for s in these cases.
member 428835
Hi PF!

Can anyone help me define a coordinate system for a circular arc that makes a specified angle ##\alpha## with a 90 degree wedge? See picture titled Geo.

As an example, a circular arc can be parameterized over a straight line by ##s##, making angle ##\alpha##, via $$\vec T = \left\langle \frac{\sin(s)}{\sin\alpha}, \frac{\cos (s) - \cos \alpha }{\sin\alpha} \right\rangle$$
 

Attachments

  • Geo.png
    Geo.png
    8.7 KB · Views: 193
Physics news on Phys.org
Hi,
joshmccraney said:
define a coordinate system
are you defining a cordinate system, or are you searching for a parametrization ?

I like to keep things simple and pick an easy example, e.g. ##\alpha = {\pi\over 2}##, Now $$\vec T = (\sin s, \cos s) $$ is a quarter circle with radius 1 and centered at the origin. For ##s\in [0, {\pi\over 2}]## oriented clockwise.

But it's a parametrization in a cartesian coordinate system.
 
BvU said:
Hi,
are you defining a cordinate system, or are you searching for a parametrization ?
Sorry, a parametrization!

BvU said:
I like to keep things simple and pick an easy example, e.g. ##\alpha = {\pi\over 2}##, Now $$\vec T = (\sin s, \cos s) $$ is a quarter circle with radius 1 and centered at the origin. For ##s\in [0, {\pi\over 2}]## oriented clockwise.

But it's a parametrization in a cartesian coordinate system.
Yep, this is simple, but what if I want ##\alpha \neq 90^\circ##?
 
Simplest case: center of circle moves along ##y=x##. (If you want to restrict to a single ##\alpha##)
And you have to do some trig to find the domain of ##s##.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K