Coriolis forces, rotating coordinate systems

Click For Summary
SUMMARY

The discussion centers on the challenges faced by students studying Coriolis forces and rotating coordinate systems, particularly in Symon's "Mechanics 3rd Ed." Chapter 7. The user expresses frustration over the lack of examples and clarity in the text, especially regarding problem 7.7, which involves calculating the Coriolis force for a freely falling body. Key concepts include the Coriolis force represented by the term -2mw x d*r/dt and the gravitational acceleration Ge(r) defined as g(r) - w x (w x r). The user seeks additional resources or companion texts that provide step-by-step examples to aid in understanding these complex topics.

PREREQUISITES
  • Understanding of vector calculus and differential equations
  • Familiarity with classical mechanics principles
  • Knowledge of angular velocity and its representation (omega)
  • Basic concepts of forces in rotating systems
NEXT STEPS
  • Research "Coriolis force derivation" for detailed mathematical explanations
  • Explore online resources like Physics Stack Exchange for problem-solving examples
  • Study "Introduction to Classical Mechanics" by David Morin for clearer explanations
  • Look into supplementary materials or companion books for Symon's Mechanics
USEFUL FOR

Students of physics, particularly those struggling with classical mechanics and rotating systems, as well as educators seeking to provide clearer instructional materials on Coriolis forces.

bcoats
Messages
8
Reaction score
0
I know that some people worship Symon's Mechanics 3rd Ed., but I find this book incredibly confusing...especially chapter 7, dealing with rotating coordinate systems. I follow the math, and perhaps the logic, but I can't even find a way to start the homework problems. The guy doesn't give any examples, and how the hell is one supposed to learn how to solve a problem when provided with nothing but dense proofs using strange notation?

For example, problem 7.7 tells us that a body is dropped from height h above the earth. We are to calculate the coriolis force as a function of time, given that it has a negligible effect on the motion, and using the velocity of a freely falling body with acceleration Ge. Neglect air resistance, assume h is small so that Ge can be taken as constant. Then, calculate the net displacement ofthe point of impact due to the coriolis force calculated previously.

OK , so Symon proves that Ge(r)=g(r)-w x (w x r). (The w represents omega, the Ge represents vector g subscript e.) I guess the coriolis force is the -2mw x d*r/dt term. How are we supposed to solve this. Are we just supposed to KNOW what w is? Nowhere in this chapter is w given for earth. I would think that maybe it would be (2pi/24hrs)*theta^ (if theta^=theta hat=unit vector in theta direction). Unfortunately, like Symon my professor rarely works examples either. I have no clue how to go about solving this or most other problems in the book. I there a website out there that, say, gives clear, step-by-step examples for solving these type of problems? Or does anyone write a "companion book" to be read side-by-side with Symon's that actually works examples for problems like his?

Why the heck did I major in Physics?
Ben
 
Physics news on Phys.org
The only person I ever heard mention Symon on this forum is me! But I do it for 5 I think because it's the only mechanics book I've read. :P

I wrote a light "summary" of the chapter on rotating coordinate systems a while back that at least answers your uncertainty regarding that the coriolis force is. Here's the thread.

https://www.physicsforums.com/showthread.php?t=58469&highlight=coriolis

You should read the chapter until you understand every single little detail about it as if you'd yourself written it. Then no problem should pose conceptual difficulties. (In theory :biggrin:)
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 46 ·
2
Replies
46
Views
5K
  • · Replies 8 ·
Replies
8
Views
4K
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K