Correctness of my equation relative to the standard given in the text

AI Thread Summary
The discussion revolves around the division of the polynomial P(x) = 4x^2 - 3x - 7 by D(x) = 2x - 1, aiming to express it in the form P(x)/D(x) = Q(x) + R(x)/D(x). The original solution used synthetic division, which was deemed incorrect by the TA, as the remainder R(x) must have a degree smaller than D(x), which is 1. It was clarified that R(x) should be a constant, not a function of x, and that long division is the appropriate method for this problem. The conversation emphasized that the remainder in polynomial division should not exceed the divisor, similar to numerical division. Ultimately, the correct approach involves recognizing that R(x) can be a constant function.
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Homework Statement



Given a polynomial P(x) and a divisor D(x), divide P(x) by D(x) and return the answer in the form P(x)/D(x) = Q(x) + R(x)/D(x)

In this case: P(x) = 4x^2 - 3x - 7
D(x) = 2x -1

Homework Equations



The one given above

The Attempt at a Solution



I solved the problem using synthetic division and ascertained: P(x)/D(x) = 2x - (x + 7)/(2x - 1)

It's part of a summer engineering program. The TA, however, counted this wrong. Could somebody tell me what the heck the problem with it is? I mean, I checked with wolfram, and evidently this is right. But... I guess not! Help is much appreciated. :)
 
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The degree of R(x) has to be smaller than the degree of D(x). Since the degree of D(x) is 1, then R(x) has to be a constant.

Also, how did you use synthetic division for this problem? Synthetic division is normally used when D(x) is in the form x - c (c being a number).
 
Your "remainder", (-x- 7)/(2x- 1) can be further divided: -(1/2)- (13/2)/(2x-1)
 
That looks absolutely terrible in terms of written form, but alright. I thought R(x) had to be a function containing x. I see now. Thanks. Oh and sorry i meant long division, I posted that around 1 last night. Haha
 
GOPgabe said:
That looks absolutely terrible in terms of written form, but alright. I thought R(x) had to be a function containing x. I see now. Thanks. Oh and sorry i meant long division, I posted that around 1 last night. Haha

Remember f(x) = 4 is a perfectly valid function in terms of x. Just because the function notation has a variable in it does not mean it HAS to be in the equation just like our constant function or even f(x) = y.

Also the thinking behind the remainder comes from number division. Say you are dividing 10 by 3. You wouldn't say that 3 goes into 10 twice remainder 4 would you? You don't want your remained to be bigger than your divisor. In this case 3 can go into 10 one more time can't it?

Similarly with polynomials 2x - 1 can go into -x - 7 one more time. It goes in -1/2 more times.
 

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