Corresponding interior and exterior angles

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The discussion revolves around solving problems involving corresponding interior and exterior angles with parallel lines. The initial question involved finding the values of x and y, where x was determined to be 48 and y was 144 based on given angle measures. The user then faced a new problem with angles involving parallel lines, specifically needing to find angle PRK when given m<NML=120. The correct answer for angle PRK was clarified to be 120 degrees, as it corresponds to angle NML due to the properties of parallel lines. The user acknowledged the mistake and expressed gratitude for the clarification.
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SO i have a problem that's "AB ll CD, Find x and y".
I got the answer of x=48, =144
Because first the measure they already gave you was 42. As well as y - 12for the other angle measure. And x was the measurement for D. blah it's too hard to explain but i got it correct.

My point is that in the next question i had no clue what to do. It was totally different but under the same category.

"In the figure, m<NML=120, PQ ll TU and KL ll NM. Find the measure of angle PRK."

How do i solve this?

Here's a visual

http://img513.imageshack.us/img513/4110/126ip.jpg"

My answer was 100. Am i correct?
 
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Richay said:
SO i have a problem that's "AB ll CD, Find x and y".
I got the answer of x=48, =144
Because first the measure they already gave you was 42. As well as y - 12for the other angle measure. And x was the measurement for D. blah it's too hard to explain but i got it correct.

My point is that in the next question i had no clue what to do. It was totally different but under the same category.

"In the figure, m<NML=120, PQ ll TU and KL ll NM. Find the measure of angle PRK."

How do i solve this?

Here's a visual

http://img513.imageshack.us/img513/4110/126ip.jpg"

My answer was 100. Am i correct?

In a word, no. Sorry!

Since KL and NM are parallel, we know that angle NML and angle KLT are equal.

Since PQ and TU are parallel, we know that angle KLT and angle KRP (which you called, more or less equivalently, PRK) are equal.

Thus angle PRK is 120 degrees also.

-Dan
 
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lol should of knew that. thanks
 
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