Cosine Rule Problem: I Can't Do a(ii) - Get Help Here

Click For Summary

Homework Help Overview

The discussion revolves around a problem involving the cosine rule, specifically focusing on part a(ii) of a question. The original poster has attempted the problem but is struggling to progress further.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between angles theta and phi, suggesting that they are expressed as inverse cosines. There is confusion regarding the application of the cosine of a sum formula, with some participants questioning the correctness of the original poster's approach.

Discussion Status

Participants are actively engaging with the problem, with suggestions to revisit previous steps and correct misunderstandings. There is an emphasis on using the correct mathematical identities and formulas, but no consensus has been reached on the next steps.

Contextual Notes

There is a mention of using radians and the implications of angle relationships in the problem, indicating that certain assumptions about angle measures are being examined.

CAH
Messages
48
Reaction score
0
Member warned about posting with no template, and posting only images
See the photo attachments of question and marking scheme and my attempt at a solution :)

I've done a(i) but I can't do a(ii).

Thanks
 

Attachments

  • image.jpg
    image.jpg
    52.7 KB · Views: 534
  • image.jpg
    image.jpg
    55.7 KB · Views: 499
Physics news on Phys.org
For a(ii) you have, basically ##\theta+\phi=\pi## (always use radians) ... with theta and phi expressed as inverse cosines of functions of x.
Your next step was to take the cosine of both sides - but you did this step incorrectly:
note: ##\cos(A+B)\neq \cos A + \cos B##
 
Still don't see what to do next
 
CAH said:
Still don't see what to do next
You could go back and fix things up as Simon suggested.

I would suggest that there was little point in taking the arccos when you did.

Notice that:

π - ∠ADB = ∠ADC

Take the cosine of both sides of this. As Simon says, use a correct form of angle difference formula for cosine.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
9
Views
2K
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
8
Views
6K