Cost of Fencing for Parking Lot: Function of Width w | Tricky Word Problem

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The discussion focuses on calculating the cost of fencing for a rectangular parking lot, where the street-facing side is more expensive. The cost per meter for the back side is $10, while the street side costs double. The length of the street side is 20 meters longer than the width. Participants are attempting to express the total cost C as a function of the width w. The proposed formulas indicate different approaches to solving the problem, highlighting the complexity of the calculations involved.
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Fencing around a rectangular parking lot costs twice as much along the side facing the street than the other three sides. The fencing along the back of the lot costs $10 per meter. Express the cost C of the fence as a function of the width w if the length of the street side of the parking lot is 20m longer than the width.

Here is the best I could come up with..

C(w)=(3w+2/3w)$10+(w+2/3w)$20

How does that look?
 
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2nd attempt..

C(w)=$10/m(5w+60m)
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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