Could neutrino anomalies be explained by Pandemonium effect?

  • Thread starter Thread starter ORF
  • Start date Start date
  • Tags Tags
    Neutrino
Physics news on Phys.org
Do you have a particular reason to expect a relation?
 
Hello

I think so: the models of nuclear reactors need beta-feeding as input, but there are nuclei which have still not been measured without Pandemonium effect.

If they are using info affected by Pandemonium effect in order to model the nuclear reactor, the expected energy distribution of beta (and therefore, antineutrino) could be affected too, and the comparison between the expected and measured energy spectrum could be explained by a incomplete (wrong) input data for the model of nuclear reactor.

I have no access to the original article, so I ask here about it :)

Greetings
 
The pandemonium effect is relevant for the gamma spectra. The beta energies are much easier to measure, and you can get the neutrino energies based on that spectrum.
Also, the pandemonium effect would go in the wrong direction, suggesting more high-energetic neutrinos.

Some mismodeling of the neutrino emission spectra can certainly be a reason for the discrepancy. It is not anything peak-like, just the spectrum is a bit different.
 
Hello

mfb said:
Also, the pandemonium effect would go in the wrong direction, suggesting more high-energetic neutrinos.

You're right, sorry for (wasting) your time.

Greetings
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top