Could somebody please explain this problem to me?(torque/angular momentum)

In summary, the conversation discusses a problem in a physics textbook where the gravitational torque of a uniform rod is compared to its rotational kinetic energy right before impact. The first part of the problem is solved using energy conservation and the second part is solved using angular momentum conservation. The conversation also mentions two different solutions with different values for L2/L1 and the use of alpha as a constant to simplify equations. The person asking for help is preparing for a final exam and is more interested in understanding the problem rather than just getting an answer.
  • #1
nlsherrill
323
1

Homework Statement



Okay I just need someone to explain to me 2 things in the solution to a problem.

Here is a link to the solution manual for the book I am using for my University Physics 1 course.

http://oak.cats.ohiou.edu/~tt106402/work/phys252/Physics%20Notes/ch10.pdf [Broken]if you search (crtl F) type in "A uniform rod of length L1 and mass", and it will take you to problem 55.

I must also note that the solution in the back of my book has L2/L1=0.36, and this solution manual online has it = 0.88, so I hope the one online is wrong, because as you will read below, I don't see the connections.

Heres a picture of the problem...its the only one I could find but you have to have cramster.

http://www.cramster.com/answers-nov-09/physics/angular-momentum-uniform-rod-length-l1-mass-08-kg-attached_705957.aspx

Homework Equations


The Attempt at a Solution



I honestly don't understand part 1. It seems to indicate that the gravitational torque of the rod = the rotational kinetic energy right before impact. Why is this? I understand that when the bar is directly below the pivot, the torque=0, so is it at that exact point that ALL of the gravitational torque gets "converted" into rotational kinetic energy? I just haven't seen this in a problem before, and there is nowhere in my book that I have found a direct relationship between torque and kinetic energy. Clearly I must be missing something.

I understand part 2, that angular momentum right before and after impact is conserved(because torque=0).

I also don't understand part 3. It seems to have "plugged in" the angular velocity solved for in part 1 into part 2, and used that to = something.

If any advice can be given on this problem it would be GREATLY appreciated, as my final exam is tomorrow..

Lastly, I don't know why alpha=m/M is used.
 
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  • #2
okay I understand step 1 now...I figured mechanical energy would not be conserved considering there was a pivot which sometimes have friction. As for the rest, I have seen 2 different solutions and they all have different values for L2/L1.
 
  • #3
nlsherrill said:
I honestly don't understand part 1. It seems to indicate that the gravitational torque of the rod = the rotational kinetic energy right before impact. Why is this? I understand that when the bar is directly below the pivot, the torque=0, so is it at that exact point that ALL of the gravitational torque gets "converted" into rotational kinetic energy? I just haven't seen this in a problem before, and there is nowhere in my book that I have found a direct relationship between torque and kinetic energy. Clearly I must be missing something.
Realize that you haven't given the figure, which is needed to describe the problem. Nonetheless, part 1 has nothing to do with torque. It's applying energy conservation to find the angular speed just before impact.

I understand part 2, that angular momentum right before and after impact is conserved(because torque=0).
OK.

I also don't understand part 3. It seems to have "plugged in" the angular velocity solved for in part 1 into part 2, and used that to = something.
Looks like energy conservation applied after the collision.

If any advice can be given on this problem it would be GREATLY appreciated, as my final exam is tomorrow..

Lastly, I don't know why alpha=m/M is used.
Why not? It's just a constant.
 
  • #4
Doc Al said:
Realize that you haven't given the figure, which is needed to describe the problem. Nonetheless, part 1 has nothing to do with torque. It's applying energy conservation to find the angular speed just before impact.OK.Looks like energy conservation applied after the collision.Why not? It's just a constant.
Thank you for your assistance Doc Al. Can you see the cramster solution? That one seems to make much more sense, and the answer is much different. Can you tell me which one is right(if either are)? By the way I am just doing practice problems to prepare for the final, so an answer means nothing compared to understanding it. I just say this because I want to emphasize that I am not just trying to get an answer out of someone for credit in the course.

But doesn't alpha represent the angular acceleration? How do you know that the ratio of the masses=the angular accel?
 
  • #5
nlsherrill said:
Thank you for your assistance Doc Al. Can you see the cramster solution? That one seems to make much more sense, and the answer is much different. Can you tell me which one is right(if either are)? By the way I am just doing practice problems to prepare for the final, so an answer means nothing compared to understanding it. I just say this because I want to emphasize that I am not just trying to get an answer out of someone for credit in the course.
I only have access to what you linked. Can you post the problem itself with the diagram? If you want me to look at some other solution, post it.

But doesn't alpha represent the angular acceleration?
Not here. Here it's just being used as a constant. But alpha is often used to represent angular acceleration, so that might be a bit confusing. (But angular acceleration is irrelevant for this problem.)
How do you know that the ratio of the masses=the angular accel?
It's not. You are misinterpreting the meaning of alpha. They are just using alpha and beta to simplify the writing of the equations.
 
  • #6
Doc Al said:
I only have access to what you linked. Can you post the problem itself with the diagram? If you want me to look at some other solution, post it.Not here. Here it's just being used as a constant. But alpha is often used to represent angular acceleration, so that might be a bit confusing. (But angular acceleration is irrelevant for this problem.)

It's not. You are misinterpreting the meaning of alpha. They are just using alpha and beta to simplify the writing of the equations.

http://www.cramster.com/answers-nov-09/physics/angular-momentum-uniform-rod-length-l1-mass-08-kg-attached_705957.aspx

I just tried the link and it didn't work the first time, but did the second. I believe this may indicated that you have to be signed in. The problem number is 67 and its from chapter 10 of Physics for Scientists and Engineers (6th) by Tipler and Mosca
 
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  • #7
Note that the problem in cramster has different masses than in your solution manual, so you can't just compare answers. (I can't see the cramster solution.)
 
  • #8
Doc Al said:
Note that the problem in cramster has different masses than in your solution manual, so you can't just compare answers. (I can't see the cramster solution.)

oh geeze your right. Here's the cramster solution:

Answer Details
M = 0.8 kg, m =0.41 kg, θmax= 60°, find L2/L1

moment of inertia of the rod I = (1/3)ML1^2

the rod rotates down, mechanical energy conservation:

Mg(L1/2) =(1/2)Iω^2 (1)

inelastic collision, angular momentum conservation:

Iω = (I +mL2^2)ω' (2)

rod and particle rotate up, mechanical energy conservation:

(I + mL2^2)(1/2)ω'^2 =((1/2)MgL1 + mgL2)*(1 -cosθmax) (3)

eliminate ω and ω' from the above 3 equations to get L2/L1 ˜ 0.47
 
  • #9
The cramster solution looks OK to me. (I didn't work out the arithmetic though.) If that's easier to understand than the solution in your solution manual, just apply the same method with the other values for the masses and compare. That way you'll confirm your understanding.
 

1. What is the definition of torque?

Torque is a measure of the rotational force applied to an object. It is calculated by multiplying the force exerted on an object by the distance from the point of rotation.

2. How is torque related to angular momentum?

Torque and angular momentum are closely related, as torque is the force that causes changes in angular momentum. In other words, torque is responsible for the rotational motion of an object.

3. Can you give an example of torque in everyday life?

One example of torque in everyday life is when using a wrench to turn a bolt. The force applied to the handle of the wrench creates a torque that rotates the bolt.

4. What is the formula for calculating torque?

The formula for torque is τ = r x F, where τ is torque, r is the distance from the point of rotation to the point where the force is applied, and F is the force applied.

5. How is torque measured?

Torque is typically measured in units of Newton-meters (Nm) or foot-pounds (ft-lb), depending on the system of measurement. It can be measured using a torque wrench or by using the formula τ = r x F.

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