- #1

swede5670

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## Homework Statement

What are the magnitude and direction of the electric field at a point midway between a -9.0 µC and a +6.0 µC charge 3.0 cm apart? Assume no other charges are nearby.

## Homework Equations

Fe= {K(q1)(q2)}/d^2

k = (8.99 x 10^9)

## The Attempt at a Solution

First I converted the µC to C =

-9 µC = -.000009 C

6 µC = .000006

Then convert 3 cm to mm = .03

(8.99 x 10^9) (-.000009) ( .000006 ) = -.48546

-.48546/d^2

-.48546/ .03

-539.4

My final answer is -539.4 but I know its wrong, can anyone tell me what I did incorrectly?