Counterweight in An Elevator System

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The discussion centers on calculating the power delivered to an elevator system with a cabin weight of 2000 kg, a counterweight of 2220 kg, and a load of 550 kg, moving upwards at a constant speed of 1.75 m/s. The textbook states the power is 5775 W, while the teacher claims it should be 44625 W. The discrepancy arises from the consideration of the counterweight's contribution to the system's energy efficiency, which the instructor failed to account for. The ambiguity in the problem's wording regarding the inclusion of the counterweight is also highlighted as a critical point of confusion.

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physicsisgrea
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An elevator system, includes a cabin of 2000 kg, a counterweight of 2220 kg and a load of 550 kg, moves at constant speed) of 1.75 m/s upwards. Find the power being delivered to the system including only the cabin and load. (Take g, acceleration of gravity = 10 m/s^2)

*The counterweight helps save energy, as the loss in G.P.E. itself goes to part of the gain in G.P.E. of the cabin and load.

The answer given by my textbook is 5775 W. However my teacher says it should be 44625 W, and I don't know which one is correct, please help me!
 
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physicsisgrea said:
The answer given by my textbook is 5775 W. However my teacher says it should be 44625 W, and I don't know which one is correct, please help me!
Your instructor failed to consider the work done by the counterweight. The wording of the problem is ambiguous: what does 'including only the cabin and load' mean? If they didn't want you to consider the effect of the counterweight, why mention it?
 

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