Counting Techniques Question: Drawing 5 specific cards out of a deck

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SUMMARY

The problem involves drawing 5 cards from a standard 52-card deck, specifically requiring exactly one Jack, one Queen, and one King. The correct calculation for the number of combinations is 49,920, achieved by selecting one of each face card and then choosing 2 additional cards from the remaining 40 cards using the combination formula. The incorrect approach of calculating 99,840 arises from treating the order of selection as significant, rather than using combinations.

PREREQUISITES
  • Understanding of combinatorial mathematics, specifically combinations
  • Familiarity with the concept of a standard deck of cards
  • Knowledge of the combination formula, denoted as nCr
  • Basic principles of probability and counting techniques
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  • Study the combination formula and its applications in probability
  • Learn about permutations and how they differ from combinations
  • Explore advanced counting techniques in combinatorial mathematics
  • Practice similar card-drawing problems to reinforce understanding
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Students studying combinatorial mathematics, educators teaching probability concepts, and anyone interested in card game strategies and calculations.

student74
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Homework Statement



We draw 5 cards out of a normal deck of 52 cards. No replacements.
How many combinations have exactly one Jack, one Queen, one King?

Homework Equations





The Attempt at a Solution



The solution = 49,920

My attempts:

I keep getting 99,840.

So 4C1 Jack, 4C1 Queen, 4C1 King, then for remaining two cards 40 possible, then 39 possible.

I go 4C1 x 4C1 x 4C1 x 40 x 39 = 99,840

Are there combinations that are repeated somewhere then? :S
 
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student74 said:

Homework Statement



We draw 5 cards out of a normal deck of 52 cards. No replacements.
How many combinations have exactly one Jack, one Queen, one King?

Homework Equations





The Attempt at a Solution



The solution = 49,920

My attempts:

I keep getting 99,840.

So 4C1 Jack, 4C1 Queen, 4C1 King, then for remaining two cards 40 possible, then 39 possible.

I go 4C1 x 4C1 x 4C1 x 40 x 39 = 99,840

Are there combinations that are repeated somewhere then? :S

After choosing 1 Jack, 1 Queen and 1 King you need to choose two more cards from 40. The number of ways of doing that =?

RGV
 
oh! thanks Ray! Why doesn't it work going 40 x 39 instead of 40C2? Does 40 x 39 not work because that takes into account order as being relevant?
 

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