Counting the states of a free particle (Periodic boundary conditions)

In summary, PBC is a mathematical trick that just gives the correct result when applied to the free particle. When continuous limit is taken L-->Infinity, the wavevector is quantized. However, when the limit is taken to large n, the integral should be replaced by sum.
  • #1
JK423
Gold Member
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Say you have a free particle, non relativistic, and you want to calculate the density of states (number of states with energy E-E+dE).
In doing that, textbooks apply periodic boundary conditions (PBC) in a box of length L, and they get L to infinity, and in this way the states become countable.
I have some questions and i'd really like your help. Thank you in advance!

1) Can someone explain to me what is the physical meaning of choosing PBC for the particle's wavefunction?

2)Why to choose boundary conditions at all for the free particle, since there are no boundaries..?

3) If PBC is just a mathematical trick that just gives the correct result, is there another more natural way of obtaining the density of states?

4) If we apply PBC, then the wavevector is quantized: k=2πn/L, where n=integer. When we take continuous limit L-->Infinity we get Δk-->dk because L is at the denominator and we can consider k to be a continuous variable. The problem is that when we make the integration, k's limits go from -Infinity to +Infinity and at these limits the approximation of treating k as a continuous variable is false, since 'n' is comparable in magnitude with L. Which means that at the limits (infinity) for large n, the integral should be replaced by sum.
So, how do we justify this? How can we prove that the error of keeping the integral all the way to infinity is negligible?
One idea that comes to my mind is the fact that the density of states is usually integrated with someother function f(k) which falls of rapidly when k-->Infinity, so the contribution of very large k is negligible. You think that this is correct?
 
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  • #2
The problem is that when we make the integration, k's limits go from -Infinity to +Infinity and at these limits the approximation of treating k as a continuous variable is false, since 'n' is comparable in magnitude with L. Which means that at the limits (infinity) for large n, the integral should be replaced by sum.
No, the reason we can treat k as a continuous variable is that Δk = 2π/L, the distance between two neighboring values of k, is small, uniformly for all k. This is true whenever L is large. It's not the size of k that counts, it's the size of Δk.
 
  • #3
Bill_K said:
No, the reason we can treat k as a continuous variable is that Δk = 2π/L, the distance between two neighboring values of k, is small, uniformly for all k. This is true whenever L is large. It's not the size of k that counts, it's the size of Δk.
Indeed.. Thanks!
 
  • #4
Any help on the first 3 questions?
 
  • #5
Is there anyone that can help please?
(I repost in order to update the thread..)
 

1. How does counting the states of a free particle with periodic boundary conditions differ from other methods?

Counting the states of a free particle with periodic boundary conditions takes into account the fact that the particle is allowed to move continuously in a finite space, rather than being confined to a specific region. This creates a periodic boundary condition, meaning that the particle will wrap around to the other side of the space if it reaches the boundary, resulting in an infinite number of possible states.

2. Why is it important to count the states of a free particle?

Counting the states of a free particle is important because it allows us to understand the behavior of particles in different systems. It also helps us analyze the properties of materials and predict how they will interact with other particles.

3. What is the formula for counting the states of a free particle with periodic boundary conditions?

The formula for counting the states of a free particle with periodic boundary conditions is given by L^3/h^3, where L is the length of the space and h is Planck's constant. This formula takes into account the periodicity of the space and the quantization of energy levels.

4. How does the size of the space affect the number of states for a free particle?

The size of the space has a direct impact on the number of states for a free particle. As the size of the space increases, the number of states also increases, resulting in a larger number of possible energy levels for the particle to occupy.

5. What are the limitations of counting the states of a free particle with periodic boundary conditions?

One limitation of this method is that it assumes the particle is in a uniform and infinite space, which may not always be the case in real-world scenarios. Additionally, it does not take into account the effects of external forces or interactions with other particles, which can also impact the number of possible states for the particle.

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