Designing a Cruise Control System Controller with Root Locus Method | Coursework

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SUMMARY

The forum discussion focuses on designing a controller for a Cruise Control System using the Root Locus method. The user expresses difficulty in understanding the method, particularly regarding the movement of poles and zeros for stability, and the implications of the graphical representation of the Root Locus. Key points include the identification of a stable pole at -0.4 and the confusion surrounding the rise time and overshoot when simulated in MATLAB. The discussion highlights the need for clarity on first-order system behavior and the relationship between rise time, overshoot, and system stability.

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  • Understanding of Root Locus method in control systems
  • Familiarity with MATLAB for system simulation
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  • Concept of stability in control systems
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Control system engineers, students studying control theory, and anyone involved in designing and simulating dynamic systems using Root Locus methods.

  • #31
Altairs said:
Does that mean that the terms risetime, settling time and overshoot etc have no meaning at all for a pure derivative controller ? But when I think again I get confused that there should be some settling time formula or for overshoot etc. If yes then what is it ?

So what is going to be steady state value in case of pure derivative controller ? Zero, always ?
The settling time is zero.
The ss value can be obtained from the final value theorem. The settling time is the time when response attains 1% or 2% of its final value. In a negative exponent exponential, what is the time when this happens?
 
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  • #32
Altairs said:
And what about PID controller how do I find rise time etc for a PID controller...It has to has some...

Obtain the time response and verify how long does it take from 10% to 90% of ss.
 
  • #33
CEL said:
In a negative exponent exponential, what is the time when this happens?

Indefinite ?
 
  • #34
Altairs said:
Indefinite ?

When isKe^{-\alpha t} equal to 0.01K or 0.02K?
 
  • #35
CEL said:
When isKe^{-\alpha t} equal to 0.01K or 0.02K?

\frac{-ln(0.01)}{\alpha}
 
  • #36
CEL said:
Obtain the time response and verify how long does it take from 10% to 90% of ss.

I have got the steady state value but how do I get the time response ? Laplace Transform ? Isn't there some shorter method ? This is because I have got a zero as well in the PI controller so the general formulae doesn't work..Any approximation ? I don't want to go for any tedious method...
 
  • #37
Altairs said:
I have got the steady state value but how do I get the time response ? Laplace Transform ? Isn't there some shorter method ? This is because I have got a zero as well in the PI controller so the general formulae doesn't work..Any approximation ? I don't want to go for any tedious method...

You must take the inverse tarnsform of the response Y(s). Don't forget that the transform of the step is 1/s, so the s in the denominator cancels the s in the numerator.
 

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