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Covariant Derivative

  1. Oct 6, 2011 #1
    The covariant derivative is different in form for different tensors, depending on their rank.

    What about other mathematical entities? The electromagnetic field A is a vector, but it has complex values. Is the covariant derivative different for complex valued vectors? And what about spinors? Matrices?
     
  2. jcsd
  3. Oct 6, 2011 #2

    haushofer

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    For spinors you have to use the spin connection to define the covariant derivative, because tensors don't transform under spinoral representations of the Lorentz group. A matrix is not a tensor or spinorial object in general, so the cov. derivative on a matrix is not defined until you specify the spinorial/tensorial character.
     
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