DrChinese said:
Zeilinger said (click to see reference) this will not work and explains why, see Fig. 2 on page 290. Basically, the which-slit information is available in principle - and thus no meaningful interference pattern arises (i.e. so nothing changes at S1 based on what you do at S2. He also indicated that his paper is based on experiments that have been performed, so I guess he thinks there is no need to re-run the experiment. Probably would explain why everyone is not rushing to do it.
Thanks for pointing to this reference. My comments are included below.
Comment 1 (Dopfer's experiment):
In Fig 2. on the top of page 290 of Zeilinger's 1999 article that you reference above, it is definitely true that there cannot be an interference pattern because which-slit information is still available, by virtue of particle b/b' in the same figure.
However, Cramer's setup (see Comment 2 below) looks closer to Fig. 3 on the bottom of page 290, which is Dopfer's experiment.
In Dopfer's setup, the question of
whether there is an interference pattern of photon 2 behind the double slit or not,
depends on where the Heisenberg detector is placed to register photon 1. There are two cases (quoting from Zeilinger's article):
Case A: The Heisenberg detector is placed in the focal plane of the lens, i.e. at distance f from the Heisenberg lens. In that case registration of photon 1 (in the Heisenberg detector) projects the state of photon 2 (in the double slit) into a momentum eigenstate which cannot reveal any position information about slit passage. In other words, which-slit information is not available. Therefore, in coincidence with a registration of photon 1 in the focal plane, photon 2 exhibits an interference pattern.
Case B: The Heisenberg detector is placed in the imaging plane of the lens, i.e. at distance 2f from the Heisenberg lens. In that case registration of photon 1 (in the Heisenberg detector) projects the state of photon 2 (in the double slit) into a position eigenstate which
can reveal position information about the path photon 2 takes through the slit assembly. In other words, which-slit information
is available. Therefore, in coincidence with a registration of photon 1 in the focal plane, photon 2 cannot exhibit an interference pattern.
So, which-slit information does not
have to be available, at least not in Dopfer's experiment, as described in Fig. 3 on page 290 of Zeilinger's article. It is of course present in Fig. 2 on the same page. But that is not Cramer's experiment.
Comment 2 (Cramer's experiment):
It seems to me that what Cramer is trying to do is to essentially take Dopfer's experiment and (a) increase the distance between the crystal and the double slit, in order to assure that photon 2 behind the double slit is always detected after photon 1, and (b) eliminate the coincidence logic. So it would still very much look like Fig. 3 on the bottom of page 290 in Zeilinger's article, just with a longer distance between the crystal and the double slit, and without the coincidence logic.
The main difference to the situation in Fig. 2 on page 290 in Zeilinger's article is of course that in Fig. 2 one of the entangled photons
first goes through the double slit before something else happens to the twin photon, whereas in Cramer's experiment it is the opposite. There, one of the photons is detected in a Heisenberg detector first,
then the other one goes through a double slit, possibly at a much later time.
Cramer's question now seems to be this: Would one still see an interference pattern in case A, and no interference pattern in case B?
For example, let's say we are in case A, i.e. the Heisenberg detector is placed in the focal plane of the lens. For simplicity, let's assume that photon 1 is registered in the Heisenberg detector at T1=1s and photon 2 in detector D2 behind the double slit at time T2=2s. Let's also assume that the experimenter always
leaves the Heisenberg detector in the focal plane of the lens, i.e. he makes the same type of measurement for
all photons that are sent through the apparatus.
Then the registration of photon 1 in the Heisenberg detector (located in the focal plane of the lens) at time T1=1s projects the state of photon 2 (which is still underway to the distant double slit) into a momentum eigenstate. From that moment on photon 2 cannot reveal any position information about slit passage anymore because the which-slit information was erased at that very moment T1=1s, once and forever.
Later, photon 2 is registered in detector D2 behind the double slit at time T2=2s.
According to Cramer, there
should be an interference pattern on detector D2 if a large number of photons is sent through the apparatus, (presumably) because the state of photon 2 at time T2=2s is
still in the momentum eigenstate that it was projected into back at time T1=1s (PS: I wonder whether this statement is actually true. Could photon 2 actually change its state between T=1s and T=2s and become more dispersed again? In any case, I think it will never be able to "re-acquire" the which-slit information that it lost at T1=1s. How would it?)
Finally, Cramer seems to believe that he doesn't need the coincidence logic, if one just uses a sufficiently large number of photons. However, in practice only a small fraction of all pairs emitted by the source is actually registered, as detectors just are not perfect. This is the detection loophole. So how can Cramer filter out the pairs that actually belong together? Perhaps he thinks this is just a practical issue. Of course, if both the source and the detectors were of very high quality (meaning that a large fraction of all pairs emitted by the source is actually registered) I can see why he thinks he doesn't need the coincidence logic. What for? There is no fringe/antifringe pair to be filtered through.
What is going on here?
Perhaps the following can shed some more light into this debate. Cramer's transmission protocal in essence seems to be this: For
each bit of information to be transmitted:
(a) The sender (the one in possesson of the crystal and Heisenberg detector D1) decides what he wants to send. He does so by selecting the location of the Heisenberg detector, either in the focal plane or the imaging plane of the lens (representing "0" or "1" by convention).
(b) The sender then sends a large number of entangled photon pairs, say N=1000, through his side of the apparatus. For each photon pair emitted, "his" twin will immediately be detected by the Heisenberg detector, while the other one is still underway.
(c) The receiver (the one in possession of the double slit and detector D2) checks whether or not an interference pattern emerges at detector D2.
I think one key issue here simply is that the photon twin traveling to the receiver still needs a finite amount of time to reach the received, even though the registration of photon 1 at the sender's side instantaneoulsy projects the state of photon 2 into a momentum or position eigenstate.
Where is the catch?
Comment 3 (comment independent of Comment 2):
Another point on Dopfer's experiment I have always wondered about after heaving read her thesis:
In both cases of comment 1 (case A or case B), the distance between the Heisenberg lens and the double slit (i.e. the distance from the Heisenberg lens back to the crystal plus the distance from the crystal to the double slit) seems to be the same -- namely 2f (I am not sure whether I read Fig. 3 correctly, but that is what it looks like in the picture anyway).
In any case, it seems to me that in order for the Dopfer experiment to work, photon 1 must be registered (in the Heisenberg detector D1) before or at least at the same time as photon 2 (in detector D2 behind the double slit).
Otherwise, one would in essence be in the situation of Fig. 2 on the top of page 290 in Zeilinger's article: photon 2 first goes through the double slit, while photon 1 is still underway. In other words, at the time when photon 2 is detected one does not know yet what type of measurement of photon 1 (still underway to the Heisenberg detector) will be made in the future. This scenario therefore represent a kind of delayed choice situation (registration of photon 1 is delayed). In this case I agree with your oroginal comment that one would of course never see an interference pattern on detector D2.
One can only try to filter out the fringe/antifringe pair ex-post, but that would of course require the conincidence circuit (otherwise one could not find out which photons 2 belong to which photons 1).
One curious question here is: What if
all photons 1 are detected with the Heisenberg detector in the focal plane of the lens (so always in case A, meaning no which-slit information is available). So there really isn't a pair of fringe/antifringe patterns, but just a single fringe pattern.
On the one hand one clearly cannot see an interference while photon 1 is still underway, so no interference pattern on detector D2. But on the other hand there cannot be an antifringe pattern because
all photons 1 are measured with the Heisemberg detector in the focal plane of the lens.
Where is the catch? (it can't be just the detection loophole of course).