I Create an Equation for 3 Offspring Rabbits

  • I
  • Thread starter Thread starter Dusto
  • Start date Start date
Dusto
Messages
2
Reaction score
0
I know that the Fibonnaci equation, Fn = Fn-1 + Fn-2, allows you to calculate (If you are using rabbits) each rabbit giving offspring to one other pair or rabbits. How does one create an equation for three offspring for each rabbit, instead of one? Instead of 0, 1, 1, 2, 3, 5, 8, 13..you have 0, 1, 1, 4, 7, 19, 38. I've been trying to create a formula that matches this, but I'm not sure if I'm doing more work than I need to. If k represents the number of offspring, the closest I have come up with is Xn = X(n-1) + X(n-2) + k + n with n being the generation number, Xn being the number of rabbits. It works for the first few generations but falls apart eventually.
 
Physics news on Phys.org
I am not sure I understand your example with the rabbits.
It looks like you are saying instead of ##X_n = X_{n-1} + X_{n-2}## you are changing the game to ##X_n = X_{n-1} +3 X_{n-2}.## But I am not sure how you generated your example sequence...since that method doesn't give 38.
 
Oh lawdy. You're right! That 6th generation should be 40. Not 38. And yes, that equation was exactly what I was aiming for. Much appreciated!
 
##\textbf{Exercise 10}:## I came across the following solution online: Questions: 1. When the author states in "that ring (not sure if he is referring to ##R## or ##R/\mathfrak{p}##, but I am guessing the later) ##x_n x_{n+1}=0## for all odd $n$ and ##x_{n+1}## is invertible, so that ##x_n=0##" 2. How does ##x_nx_{n+1}=0## implies that ##x_{n+1}## is invertible and ##x_n=0##. I mean if the quotient ring ##R/\mathfrak{p}## is an integral domain, and ##x_{n+1}## is invertible then...
The following are taken from the two sources, 1) from this online page and the book An Introduction to Module Theory by: Ibrahim Assem, Flavio U. Coelho. In the Abelian Categories chapter in the module theory text on page 157, right after presenting IV.2.21 Definition, the authors states "Image and coimage may or may not exist, but if they do, then they are unique up to isomorphism (because so are kernels and cokernels). Also in the reference url page above, the authors present two...
I asked online questions about Proposition 2.1.1: The answer I got is the following: I have some questions about the answer I got. When the person answering says: ##1.## Is the map ##\mathfrak{q}\mapsto \mathfrak{q} A _\mathfrak{p}## from ##A\setminus \mathfrak{p}\to A_\mathfrak{p}##? But I don't understand what the author meant for the rest of the sentence in mathematical notation: ##2.## In the next statement where the author says: How is ##A\to...
Back
Top