Cross product and the angles of a prallelogram

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Cross product and the angles of a prallelogram's diameters

Homework Statement



With the help of cross product prove: if the angle between the diameters of a parallelogram is 90 degrees, then the parallelogram is a rectangular.

Homework Equations



A[tex]\times[/tex]B=(surface of the parallelogram)


The Attempt at a Solution

 
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What is [tex]|\mathbf{A} \times \mathbf{B}|[/tex]? How does it depend on the angle between the two vectors?
 
A and B are not the diameters, they are the sides. As I mensioned [tex]|\mathbf{A} \times \mathbf{B}|[/tex]= (the surface of the parallelogram)
 
what are the diameters? the diagonals? if so you should be able to write them as a vector sum of the sides...