Curl of the partial derivative of a scalar

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SUMMARY

The discussion centers on the mathematical concept of taking the curl of the partial derivative of a scalar function. It is established that if A is a scalar function A(x,y,z,t), then the partial derivative with respect to time t results in another scalar function. The gradient of this scalar function produces a vector field, but the curl operator can only act on spatial components. Importantly, the curl of the gradient of a scalar field is definitively zero.

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  • Understanding of scalar functions and their derivatives
  • Familiarity with vector calculus concepts, particularly curl and gradient
  • Knowledge of spatial and temporal components in mathematical functions
  • Basic principles of covectors and their application in vector fields
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  • Learn about covectors and their role in vector field analysis
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JerryG
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I have a problem where part of the solution involves taking the Curl of the partial derivative of a scalar.

If A is a scalar function, then wouldn't taking the partial derivative of A with respect to time "t" just give another scalar function?
 
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So you have A(x,y,z,t) and want to find partial wrt t, then yes it is a scalar function, finding the gradient would yield vector field
 
You can take the curl only wrt spatial components. And the curl operator must act on at least on a covector. The gradient wrt one of the components of a scalar function is such type of covector. But the curl of gradient of a scalar fiels is 0.
 

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