Current and voltage relationship in an electric motor

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SUMMARY

The discussion centers on the relationship between current and voltage in electric motors, specifically a pumping motor that requires 63 A at 390 VAC and 72 A at 365 VAC while maintaining a power output of 37 kW. The power formula for three-phase motors is defined as Power = 1.732 * V * I * PF, illustrating that lower voltage necessitates higher current to maintain torque. Additionally, the speed-torque curve of induction motors indicates that as voltage decreases, the motor operates on a lower torque curve, requiring more current to achieve the desired torque.

PREREQUISITES
  • Understanding of three-phase power calculations
  • Familiarity with the speed-torque curve of induction motors
  • Knowledge of Ohm's Law and its application in electrical systems
  • Basic concepts of power factor (PF) in electrical engineering
NEXT STEPS
  • Research the impact of voltage variations on motor performance
  • Learn about the pump affinity laws and their implications for motor operation
  • Study the speed-torque characteristics of induction motors
  • Explore the effects of long extension cords on motor efficiency and safety
USEFUL FOR

Electrical engineers, motor technicians, and anyone involved in the design or maintenance of electric motors, particularly in pumping applications.

bachir1994
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Hello,
I can not understand that a motor (pumping) requires a current of 63 A under a voltage of 390 vac, and requires a current of 72 A under a voltage of 365 vac. Normally when the voltage increases the current increases with (ohm law). Is that the power delivered by the engine which is 37 kw is maintained.
THANK YOU.
 
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bachir1994 said:
Hello,
I can not understand that a motor (pumping) requires a current of 63 A under a voltage of 390 vac, and requires a current of 72 A under a voltage of 365 vac. Normally when the voltage increases the current increases with (ohm law). Is that the power delivered by the engine which is 37 kw is maintained.
THANK YOU.

Power (3 phase) = 1.732 * V * I * PF
Power in watts, I=Amps, V=Volts, PF= power factor

Creating 37 kW of shaft power requires less current when the motor is supplied at a higher line voltage, and needs more current at lower line voltages.

An added consideration is shaft speed varies proportionally with line voltage, but pump power varies as the cube (see: pump affinity laws).

Induction Motor Characteristic - Voltage Effects.jpg

Is the motor voltage rating 380V? If so, then 390V is 2.6% above nominal, and 365V is 3.9% below nominal nameplate rating.
Inspect the generic curves above to gain a sense how voltage variation affects motor performance.
 
Three phase motors operate at fixed RPM and draw whatever current they need to generate the torque they need to keep spinning or fail trying.
 
thank you,
Therefore it is the velocity that imposes the torque therefore the current, it is a natural regulation of the phenomenon. Nothing is created, nothing is lost all changes.
 
Induction motors have something called a "Speed-Torque" curve. It looks like this.
http://www.engineeringtoolbox.com/electrical-motors-torques-d_651.html
(the obvious annotations are mine)
speed-torque1.jpg

Note how small is the operating range , circled in purple.
When you lower voltage, the motor runs now on a lower torque curve.
So it has to 'walk back up' that curve by slowing down a little bit , in order to make desired torque.
Walking up the torque curve also walks up the current curve. It will require more than normal running current to make full torque at reduced voltage.

That's why real long extension cords can cause an induction machine like a fridge or pump to burn up its motor.

hope this helps

old jim
 
Last edited:
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thank you jim hardy
your explanation is very good, and it's ok for me. I begin to see things clearer
 
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bachir1994 said:
I begin to see things clearer

That's what counts. Keep up your good work !

old jim
 

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