Current in the primary coil of transformers used in rectifier circuits

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SUMMARY

The current in the primary coil of transformers used in full wave rectifier circuits adheres to the relationship V(s)I(s) = V(p)I(p), but the specific values to use depend on the calculation required. For peak and RMS current calculations, the peak voltage is applicable, while the average current over a complete cycle mathematically results in zero due to the sine wave nature of the current. Understanding these principles is essential for accurate transformer current analysis.

PREREQUISITES
  • Understanding of transformer operation in electrical circuits
  • Knowledge of full wave rectifier circuits
  • Familiarity with peak and RMS voltage/current calculations
  • Basic grasp of sine wave functions and their properties
NEXT STEPS
  • Research transformer primary coil current calculations in detail
  • Learn about full wave rectifier circuit design and analysis
  • Study the differences between peak, RMS, and average values in AC circuits
  • Explore the mathematical properties of sine wave functions in electrical engineering
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Electrical engineers, students studying circuit design, and professionals involved in transformer and rectifier circuit analysis will benefit from this discussion.

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Can anyone please clarify if the current in the primary coil of the transformer follows V(s)I(s)=V(p)I(p) when i am trying to figure out the peak, surge and average current through the primary coil of a transformer in a full wave rectifier.

Also, if it does, do I just use the peak voltage or the rms value?
 
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It does and it does not . That depends on what are u trying to calculate.

You can use this relationship to calculate the "peak" voltage / current and R.M.S value , depending on what you need.

One more thing, as long as the average current or voltage is concerned it would mathematically be zero since the Current is a sine wave function . The mean value of such a current over one complete cycle would be zero .
 

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