What is the Voltage Compliance Range of a Current Source?

AI Thread Summary
The discussion focuses on determining the voltage compliance range of a current source and the load resistor range for proper circuit function. The calculated values indicate that the voltage compliance range is between 9V and 10V, assuming a constant supply voltage of 10V. It is emphasized that the circuit operates as a current source only if the 8.2K resistor maintains a voltage of +10V. Additionally, the high voltage limit is influenced by the transistor's breakdown voltages, which cannot be fully determined with the provided data. Clarification on "compliance range" is needed, particularly regarding how varying load resistors affect the circuit's performance.
Duave
Messages
81
Reaction score
0
Thank you for any help that you can offer.

Did I answer all of the questions correctly and thoroughly? Can you please find any errors, and point them out to me so that I can fix them?

Homework Statement



Show that :

VB = 1.6V
VE = 1.0V
IE = 1.0 mA
IL = 1.0 mA
What is the voltage compliance range of the current source?
For what range of load resistors RL will the circuit function as a current source?

https://scontent-a.xx.fbcdn.net/hphotos-prn1/t1.0-9/1012267_10151937081750919_819156677_n.jpg

Homework Equations



RB1/RB2 = {10V - VB}/VB
...................
IL = IE = VB - 0.6/RE
.................
VLimit < Vcomp < {VRE/RE}RL = 1.03mA[/B]
.....................
iout = Vin/RE
............

The Attempt at a Solution



2(a)1

RB1/RB2 = {10V - VB}/VB
..................
8.2k/1.6k = {10V - VB}/VB
.............
5.125VB = {10V - VB}
............
5.125VB + VB = 10V
............
6.125VB = 10V
........
VB = 10V/6.125
.......
VB = 1.63V
......

2(a)2
.......
IL = IE = VB - 0.6/RE
.................
IL = IE = 1.63 - 0.6/1000k
.............
IL = IE = 1.03/1000k
............
IL = IE = 1.03mA
..........
VB - VBE = VE
.............
VE = 1.03V
......
VE/RE = 1.03V/1000k
............
IE = VE/RE = 1.03mA
...............


What is the voltage compliance range of the current source?

The device is in comlpliance when:

VLimit < Vcomp < {VRE/RE}RL = 1.03mA[/B]
...............
VCC - ILRE < Vcomp < {VRE/RE}{VCC/IE}
.................
10V - (0.001A)(1000[ohms]) < Vcomp < {1V/1000[ohms]}{10V/0.001A}
.....................
10V - 1V < Vcomp < 10V
.........
9V < Vcomp < 10V
.........


For what range of load resistors RL will the circuit function as a current source?

The range of load resistors can be found by:

iout = Vin/RE
............
9V/1000[ohms] < Vcomp/RL[ohms] < 10V/1000[ohms]
...................
Your assistance will be greatly appreciated
 
Physics news on Phys.org
"Compliance range" needs to be better defined.

The circuit is a current source for R_L only if the 8.2K resistor stays at +10V.
Then you can determine how low Vcc to R_L can be before the transistor saturates.

There is in addition a high voltage limit due to the breakdown voltages of the transistor, but that can't be determined with the data you're given.

The last question's answer depends on the voltage to R_L as well as the value of R_L, so I guess assume Vcc = 10V for R_L.
 
  • Like
Likes 1 person
rude man said:
"Compliance range" needs to be better defined.

The circuit is a current source for R_L only if the 8.2K resistor stays at +10V.
Then you can determine how low Vcc to R_L can be before the transistor saturates.

There is in addition a high voltage limit due to the breakdown voltages of the transistor, but that can't be determined with the data you're given.

The last question's answer depends on the voltage to R_L as well as the value of R_L, so I guess assume Vcc = 10V for R_L.


@rude man


Thank you. I will make corrections.
 
@rude man,


If the compliance voltage is the range of output voltage in a constant current (dc) power supply over which the load regulation is within certain limits, how can I use this knowledge to verify that my last answer is correct. Can the variable load resistor range from 0 to 8k4 ohms. If it is higher than that, what will happen?

Thank you
 
If your load is 8000 ohms, what is the collector voltage going to be?
If it's 9000 ohms, what then?

Hint: if the emitter to collector voltage is < about 0.2V the transistor is in saturation.

BTW this is not voltage compliance. It assumes the voltage to RL is a constant +10V.

Voltage compliance is a function of R_L. Try to figure out how low the voltage at the top of R_L can be for a given R_L.
 
Back
Top