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## Homework Statement

What diameter should the nichrome wire in the figure be in order for the electric field strength to be the same in both wires?

## Homework Equations

σ = 1/ρ

J = σ*E......I/A = σ*E.........I = σ*E*A

Then, equate the current equations for each wire.

## The Attempt at a Solution

__nichrome__

__aluminum__

σ*A = σ*A

Since, the E-fields are to be the same, they should just cancel out.

ρ(aluminum)= 2.82*10^-8 Ωm

ρ(nichrome)= 1.1*10^-6 Ωm

pi*r^2 = σ(Al)*A/σ(nichrome)

...& after solving for r, I calculated the diameter to be approximately 6.246 mm, however this was apparently wrong, but I have no idea where I went wrong. Help would be greatly appreciated!