1. The problem statement, all variables and given/known data What diameter should the nichrome wire in the figure be in order for the electric field strength to be the same in both wires? 2. Relevant equations σ = 1/ρ J = σ*E......I/A = σ*E.........I = σ*E*A Then, equate the current equations for each wire. 3. The attempt at a solution nichrome aluminum σ*A = σ*A Since, the E-fields are to be the same, they should just cancel out. ρ(aluminum)= 2.82*10^-8 Ωm ρ(nichrome)= 1.1*10^-6 Ωm pi*r^2 = σ(Al)*A/σ(nichrome) ...& after solving for r, I calculated the diameter to be approximately 6.246 mm, however this was apparently wrong, but I have no idea where I went wrong. Help would be greatly appreciated!