Cyclic Permutation in C: Create Alphabet Pattern with Nested For Loops

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The discussion focuses on generating cyclic permutations of the English alphabet using nested for loops in C. One participant suggests using the modulo operator to facilitate the wrap-around from 'z' back to 'a', which is crucial for achieving the desired pattern. An alternative method is proposed that involves shifting characters without using modulo, but it only employs a single loop. The importance of understanding the modulo operation for this task is emphasized, as it aids in correctly implementing the cyclic nature of the alphabet. Overall, the conversation highlights different approaches to solving the problem while reinforcing the utility of the modulo operator.
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Use nested for loops to produce the following pattern of cyclic permutations of the English
alphabet:
abcde...yz
bcdef...za
cdef...zab
...
zabcde...xy
HINT: you may find the modulo (remainder) operator % useful.

I have an idea of how to do this but it would not use the modulo operator. I thought of saving the first letter of an array into a variable, shifting everything else down one and putting it at the end. This also would only implement a single for loop. Any clues would be greatly appreciated.
 
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Yes, there are probably a million ways to do this, but I suggest that you have one loop generating the first character of each string and an inner loop (since that what was asked for) generating the successive letters of each string - using modulo operator to make the wrap from z to a.
 
Thanks a lot. Took me a bit to get the wrap around to work properly but I got it. I don't think modulo was very intuitive to me before but now I get it.
 

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