Two solid cylinders are placed on an inclined plane with inclined angle Θ. Both mass of cylinders are m, but the radius bigger cylinder is two times the radius of small cylinder. A string links the big cylinder's center to small cylinder's top (see picture). Both cylinders are freed from static condition and then roll down the inclined plane without slipping.
Determine the relation between the big cylinder tangential acceleration and its center of mass acceleration
atangential = α r[/B]
The Attempt at a Solution
I think that rolling without slipping means the tangential acceleration equals the center of mass acceleration.
I think that the acceleration of big cylinder center of mass equals the tangential acceleration of the small cylinder.
It rolls without slipping means that the big cylinder center of mass acceleration equals its tangential acceleration.
So, I think atan = acm
But, my book says that
atan = acm + α r
acm = α r
atan = 2 acm
But, I don't understand how atan = acm + α r comes from
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