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Cylindrical Wall Heat Equation

  1. Dec 4, 2011 #1
    I'm a little bit rusty with my differential equations, and can't seem to see how solving for 1/r d/dr (r dT/dr)=0 has the solution T(r)=C_1*ln⁡(r)+C_2
     
  2. jcsd
  3. Dec 4, 2011 #2
    integration of d/dr (r dT/dr)=0 leads to (r dT/dr) = C1
    dT = C1 dr/r
    integration of dT=C1 dr/r leads to t = C1 ln(r) + C2
     
  4. Dec 4, 2011 #3
    Thanks
     
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