D'alembert solution for the semi-infinite string

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    D'alembert String
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SUMMARY

The discussion focuses on solving the wave equation for a semi-infinite string using the d'Alembert solution. The initial conditions specified are u(0,t)=0 and u(x,0)=0, with the time derivative u_t(x,0) defined as \(\frac{x^2}{1+x^3}\) for \(x \geq 0\) and 0 for \(x < 0\). The derived solution is presented as \(u(x,t)=\frac{1}{2c}\left( \int^{x+ct}_{x-ct} dy\, b(y) - \int^{-x+ct}_{-x-ct} dy\, b(y) \right)\) where \(b(y)=\frac{y^2}{1+y^3}\). The final expressions for \(u(x,t)\) are confirmed as \(\dfrac{1}{6c}\ln\left[\dfrac{1+(x+ct)^{3}}{1+(x-ct)^{3}}\right]\) for \(x \geq ct\) and \(\dfrac{1}{6c}\left[\ln\left(\dfrac{1+(x+ct)^{3}}{1+(ct-x)^{3}}\right)\right]\) for \(x < ct\).

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Homework Statement


Find the solution of the wave equation using d'Alembert solution.

Homework Equations


u(0,t)=0[/B] and u(x,0)=0
u_t(x,0)=\frac{x^2}{1+x^3}, \, x\geq0
u_t(x,0)=0, \, x&lt;0


The Attempt at a Solution


For a semi infinite string we have the solution
u(x,t)=\frac{1}{2}\left( a(x-ct)+a(x+ct)-a(-x-ct)-a(-x+ct) \right)+\frac{1}{2c}\left( \int^{x+ct}_{x-ct} dy\, b(y) - \int^{-x+ct}_{-x-ct} dy\, b(y) \right)
with u(x,0)=a(x)=0 so
u(x,t)=\frac{1}{2c}\left( \int^{x+ct}_{x-ct} dy\, b(y) - \int^{-x+ct}_{-x-ct} dy\, b(y) \right)
where

b(y)=<b>\frac{y^2}{1+y^3}</b>

Is this right?
 
Last edited:
Thsi is what I came up with
for x \geq ct
u(x,t)=\dfrac{1}{6c}\ln\left[\dfrac{1+(x+ct)^{3}}{1+(x-ct)^{3}}\right]
and x &lt; ct
u(x,t)=\dfrac{1}{6c}\left[\ln\left(\dfrac{1+(x+ct)^{3}}{1+(ct-x)^{3}}\right)\right]
 

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