Data Management - Probability of Cards

[marialovesphysics]

Homework Statement

I have tried solving this question multiple times, and I was unable to do so.
Three cards are drawn from a deck of cards, with replacement. The 13 spades have been removed from the deck. Find the probability that:
A) at least two hearts are chosen.

B) the last two cards are diamonds or the first card is a king.

C) they are 3 aces, given they are not face cards

Relevant Equations

Fractions, P(A or B) , P(A and B) , P (A``````````````|B) Either of them could be required and maybe other stuff too

Here is my work so far:
52-13=39 There are 39 decks of cards left since the spades were removed.
a)
Then there 13 hearts therefore, (13/39 ) * (13/39 ) that would be two hearts but I am not sure what to do next. But I am sure that it would be 39 cards and 13 hearts on top (maybe) cus it is replacement.
I am not sure if I am doing this correctly. Please let help me with this urgent matter.

 

[FactChecker]

You have the probability that the first two cards, A&B, are a heart. In that situation, the third card, C, can be anything. So what is your calculated probability for that situation (A=heart, B=heart, C=anything)? Then you have to figure out how many different ways the three cards could have been ordered: ABC, ACB, BCA, BAB, etc. Since this is with replacement, the same probability is true for every way to order the cards. So what would your final answer for a) be?