- #1
BobMarly
- 19
- 0
Prb:(x^4+4*x^2+16)y"+4(x-1)y'+6xy=0
P=(x^4+4*x^2+16) Q=4(x-1) R=6x
P=0 for - 1 - 3^(1/2)*i
1 - 3^(1/2)*i
- 1 + 3^(1/2)*i
1 + 3^(1/2)*i
Q=0 for 1
R=0 for 0
Do we ignore Q & R, plotting P, then find shortest distance which would equal 2?
P=(x^4+4*x^2+16) Q=4(x-1) R=6x
P=0 for - 1 - 3^(1/2)*i
1 - 3^(1/2)*i
- 1 + 3^(1/2)*i
1 + 3^(1/2)*i
Q=0 for 1
R=0 for 0
Do we ignore Q & R, plotting P, then find shortest distance which would equal 2?