Prb:(x^4+4*x^2+16)y"+4(x-1)y'+6xy=0(adsbygoogle = window.adsbygoogle || []).push({});

P=(x^4+4*x^2+16) Q=4(x-1) R=6x

P=0 for - 1 - 3^(1/2)*i

1 - 3^(1/2)*i

- 1 + 3^(1/2)*i

1 + 3^(1/2)*i

Q=0 for 1

R=0 for 0

Do we ignore Q & R, plotting P, then find shortest distance which would equal 2?

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# DE: Lower Bound for radius of convergence

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