Hello everyone. I was loooking over some notes and I noticed this problem i had a question mark next too. Supose that you are dealt four cards instead of 5. How many 4 card hands consist of two pairs (two cards of one denomination and two cards of a second denomoniation)? The answer is 2,808. It was found by: (13 choose 2) * (4 choose 2)^2 But i'm confused because if you are choosing 2 cards of one denomination, thats like choosing two 5's. There is only one 5 in every 13 cards or suites correct? so if you have (13 choose 2) that means your choosing 2 cards out of 1 suit weither it be hearts, diamonds, clubs or spades. So how can you be choosing 2 of the same numbers from a set of 13? Or are they saying, they are chooosing 2 cards of 1 suit, such as a 4 and a 10, and later they are choosing 2 cards to match that suit, such as a 10H and a 10C, that would be one (4 choose 2) and the other would be 4H, and a 4D that would be the other (4 choose 2)? I think i got it by writing this question but just making sure, thanks!