Death Penalty and False Positives

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The discussion centers on the implications of the death penalty in the context of wrongful convictions. It examines the probabilities associated with executing individuals, specifically questioning the likelihood that all 873 people executed from 1977 to 2003 were truly guilty. The calculations presented suggest that the probability of all executed individuals being guilty is 0.99 raised to the power of 873, while the probability of at least one being innocent is derived from the complementary probability. This raises significant concerns about the potential for false positives in capital punishment cases. The conversation highlights the ethical dilemmas surrounding the death penalty and the risk of executing innocent individuals.
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Discussing wheather to convict someone charged with murder and give them the death penalty, consider the variables "reality (defendant guilty, defendant innocent) and "decision" (convict, acquit)

Jurors are asked to convict a defendant if they feel the defendant is "guilty beyond reasonable doubt" Suppose this means given the defendant is executed, the probability that s/he is truly guilty is 0.99. For the 873 people put to death from 1977 until September 2003, find the probability that:

i) they were all truly guilty

ii) at least on of them was actually innocent
 
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Okay, is P(all those executed were actually guilty)= 0.99^873?
P(at least one innocent)= 0.01^873

Anyone who can let me know if I'm on the right track is appreciated =)
 
0.01^873 is the probability that they're all innocent

P(at least one of them is innocent) = 1 - P(all 873 are guilty)
 
I was reading a Bachelor thesis on Peano Arithmetic (PA). PA has the following axioms (not including the induction schema): $$\begin{align} & (A1) ~~~~ \forall x \neg (x + 1 = 0) \nonumber \\ & (A2) ~~~~ \forall xy (x + 1 =y + 1 \to x = y) \nonumber \\ & (A3) ~~~~ \forall x (x + 0 = x) \nonumber \\ & (A4) ~~~~ \forall xy (x + (y +1) = (x + y ) + 1) \nonumber \\ & (A5) ~~~~ \forall x (x \cdot 0 = 0) \nonumber \\ & (A6) ~~~~ \forall xy (x \cdot (y + 1) = (x \cdot y) + x) \nonumber...

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