DeBroglie wavelength considering relativistic effects

  • Thread starter *Alice*
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"Electrons are accelerated by a potential of 350kV in an electron microscope. Calculate the de Broglie wavelength of those electrons taling relativistic effects into account"


I attempted the following:

W = W(kin) = 350keV

now

[tex]W(kin)= (1-gamma)mc^2 [/tex]

so, now one could solve for gamma and find the velocity of the particle.


afterwards [tex] p=m*v=h/lambda [/tex]

HOWEVER: I get a negative result in a root when I try to solve for v. Therefore I think that my energy formula must be wrong (I already excluded calculation errors). Can anyone see it?
 

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  • #2
nrqed
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*Alice* said:
"Electrons are accelerated by a potential of 350kV in an electron microscope. Calculate the de Broglie wavelength of those electrons taling relativistic effects into account"


I attempted the following:

W = W(kin) = 350keV

now

[tex]W(kin)= (1-gamma)mc^2 [/tex]

It's [itex] (\gamma -1) m c^2 [/itex] (the gamma factor is always larger or equal to 1)


Patrick
 

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