- #1
ForTheGreater
- 22
- 0
Decide the linear interpolant
f(-pi)=4 f(-pi/2)=5/4 f(0)=1 f(pi/2)=-3/4 f(pi)=0
the function is (1/pi2 ) (x-pi)2 - cos2 (x-pi/2)
Don't know how to do this. I tried lagrange basis functions f(x0)(x1-x)/(x1-x0)+f(x1)(x-x0)/(x1-x0)
But it doesn't turn out right.
The answer for the first interpolant (interval -pi to -pi/2) is: 4-11(x+pi)/(2pi)
f(-pi)=4 f(-pi/2)=5/4 f(0)=1 f(pi/2)=-3/4 f(pi)=0
the function is (1/pi2 ) (x-pi)2 - cos2 (x-pi/2)
Don't know how to do this. I tried lagrange basis functions f(x0)(x1-x)/(x1-x0)+f(x1)(x-x0)/(x1-x0)
But it doesn't turn out right.
The answer for the first interpolant (interval -pi to -pi/2) is: 4-11(x+pi)/(2pi)