I Decoherence and direction of causality

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The discussion centers on the implications of decoherence in quantum mechanics, specifically regarding the relationship between measured values and outcomes. The expression provided suggests a link between measuring value A and outcome M_A, raising questions about causality direction. Participants explore whether measuring A implies M_A or vice versa, with a focus on the role of entanglement in these interpretations. Clarification on how entanglement influences these causal relationships is sought. Understanding these connections is crucial for grasping the nature of quantum measurements and their implications.
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If I use the expression ##(|A\rangle+|B\rangle)|M\rangle \rightarrow |A\rangle|M_A\rangle+|B\rangle|M_B\rangle## for decoherence, does that mean that we can infer that, IF the measured value is ##A## that THEN we will measure ##M_A##, OR that IF we measure ##M_A## THEN the measured value must have had the value ##A##? Are both legitimate?
 
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Little bump because I rephrased the question a little. :wink:

I think the answer to my question involves entanglement. If so it would be appreciated to have it explained in the context of my question. Thanks! :smile:
 
For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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