Decomposition of the wave-vector in terms of wavelength

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SUMMARY

The discussion focuses on the decomposition of the wave-vector in relativistic optics, specifically expressing k_x, k_y, and k_z in terms of wavelength (λ), the speed of light (c), and the angle (θ) between a source and an observer. The user correctly derives k_x as k_x = 2πcos(θ) / λ and k_y as k_y = 2πsin(θ) / λ. The challenge arises in expressing k_z, where a suggestion is made to set k_z = 0 for simplification.

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  • Familiarity with trigonometric functions and their applications
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watty
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Im attempting a problem in relativistic optics that's asking me to write k_x, k_y and k_z in terms of lambda, c, and theta (theta being the angle between a source and an observer, at rest relative to each other). Lamda is the wavelength in this reference frame. I started off using trigonometry to say that { k_x = 2*pi*cos(theta) / lambda } and equivalent but with sin(theta) for k_y but then how do I express k_z ? i can't see homework to it without introducing an angle between the x and z axis!

help please!
 
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Hi watty! :smile:

(have a theta: θ and a lambda: λ and a pi: π :wink:)

uhh? :confused: you're in charge! :wink:

so just put kz = 0. :smile:
 

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