Decoupling Capacitor for a PCB Track

[Weaver]

Homework Statement

Homework Equations

3. The Attempt at a Solution [/B]
Currently stuck on the question relating to the value of capacitance across X1/Q1 to reduce the voltage to 1 LSB

I have calculated the voltage of the 1LSB to be 0.8507 mV

ADC Range/Resolution 3.3V/2^12

I have also calculated the voltage across the PCB track to be 10 + 64pi mV

Z = 0.1 + j2pi(1.6 x 10^6)(0.2 x 10^-6)
= 0.1 + j16/25 pi

V = IZ
V = (100 x 10^-3)(0.1) + j16/25 pi)
V = 10 + j64pi mV

For the capacitance, can I just used an equation I have seen before,

C = I/(Vripple x f)

with Vripple as 0.8507 mV
or

Do I have to calculate the parallel impedance of a the PCB track with a capacitor and find a value for C such that the magnitude of the voltage with 100 mA is less than 0.8507 mV?

 

[trurle]

C=(Iripple*Ton)/Vmax=0.1A*(1/3.2)*1us/0.85mV=37uF

 

[Weaver]

C=(Iripple*Ton)/Vmax=0.1A*(1/3.2)*1us/0.85mV=37uF

Great! Thank you very much!