Definite Integral: Evaluate ∫1^8 (3 - y^(1/3) / y^(2/3)) dy | Problem #24"

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SUMMARY

The discussion focuses on evaluating the definite integral ∫ from 1 to 8 of the function (3 - y^(1/3) / y^(2/3)) dy. The integral is simplified to ∫(3*y^(-2/3) - y^(-1/3)) dy, which is then evaluated to yield the result of 9/2. The calculations confirm the correctness of the answer provided by the participant, demonstrating a clear understanding of integral calculus.

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rowdy3
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Evaluate each Definite integral.
∫ lower limit 1, upper limit 8. 3 - y^(1/3) / y^(2/3) ; dy
Here's a link if you have trouble understanding my problem. It's #24.
http://pic20.picturetrail.com/VOL1370/5671323/23643016/396407299.jpg
I did
∫(3*y^(-2/3) - y^(-1/3)) dy from 1 to 8

9*y^(1/3) - 3/2*y^(2/3) eval. from 1 to 8

= 9(2) - 6 - 9 + 3/2

= 3 + 3/2 = 9/2
 
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Greetings! Good work, your answer is correct.
 

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