Is the Integral Solved Using Integration by Parts?

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SUMMARY

The integral from 0 to 1 of the function (x^2)(sqrt(9x+8))dx can be solved using integration by parts. In this method, let u = 9x + 8, leading to du = 9dx, and choose v = (x^3)/3, with dv = x^2dx. The solution involves applying the integration by parts formula [uv - integral of (vdu)], resulting in (x^3)/3 * (9x+8) minus the integral of [(x^3)/3 * 9dx]. This approach effectively simplifies the integral for evaluation.

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MillerL7
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Consider the Integral: a=0 b=1 (x^2)(sqrt(9x+8))dx

Does u=(9x+8) ?
can we factor out the x^2?

We have to give the value that the definite integral is
 
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you have to use integration by parts. you want

u= 9x+8
du=9dx
v= (x^3)/3
dv=x^2dx

then figure out [ uv - integral of (vdu) ]
(x^3)/3 * (9x+8) - integral of [ (x^3)/3 * 9dx)]
 

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