Definite Integral of Absolute Value Function (Calc I)

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To solve the integral $$\int_{0}^{2\pi} |e^{\sin(x)}\cos(x)| \, dx$$, it is necessary to break the integral into segments where the function is positive and negative, integrating each part separately. The simplification leads to the result of $$2e - \frac{2}{e} \approx 4.7$$. While the method may seem tedious, it is the standard approach for handling absolute value functions in integrals. The discussion confirms that breaking down the integral is the correct strategy. Overall, the approach emphasizes the importance of understanding the behavior of the function across its domain.
physicsdreams
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Homework Statement



$$\int_{0}^{\ 2\pi} \ |e^{sin(x)}cos(x)| \, dx$$

I know that it simplifies to $$ 2e- \frac{2}{e} ≈ 4.7 $$ I'm not sure how to approach this problem. Do I just break the integral up into the domains where it's positive and negative and integrate each component separately as I would with a much simpler absolute value function?

Thanks in advance,

physicsdreams
 
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physicsdreams said:

Homework Statement



$$\int_{0}^{\ 2\pi} \ |e^{sin(x)}cos(x)| \, dx$$

I know that it simplifies to $$ 2e- \frac{2}{e} ≈ 4.7 $$ I'm not sure how to approach this problem. Do I just break the integral up into the domains where it's positive and negative and integrate each component separately as I would with a much simpler absolute value function?

Thanks in advance,

physicsdreams

Yes, that's exactly what you should do.
 
Dick said:
Yes, that's exactly what you should do.

Wow, you're quick! Thanks for the help, Dick. I was hoping there would be a less tedious method to go about solving problems such as these, but I guess that's math for ya'.

Thanks again!
 
physicsdreams said:
Wow, you're quick! Thanks for the help, Dick. I was hoping there would be a less tedious method to go about solving problems such as these, but I guess that's math for ya'.

Thanks again!

Well, it was a pretty easy answer. You're very welcome.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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