Definite integral with x^2+c in the denominator

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Hypatio
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Homework Statement

Homework Equations



solve the definite integral

[tex]\int_{2.6}^{5.5} \frac{1}{x^2+9}dx[/tex]

The Attempt at a Solution



ln(5.5^2+9)-ln(2.6^2+9) doesn't seem correct
 
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Hypatio said:

Homework Statement




Homework Equations



solve the definite integral

[tex]\int_{2.6}^{5.5} \frac{1}{x^2+9}dx[/tex]

The Attempt at a Solution



ln(5.5^2+9)-ln(2.6^2+9) doesn't seem correct

If you take the derivative of log(x^2+9) you will not get 1/(x^2+9) (at least if you don't forget the chain rule). You need a trig substitution to do that integral.