(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Evaluate:

[tex] \displaystyle \int_{\pi/6}^{\pi/2} \frac{\cos(z)}{\sin^{9}(z)}\, dz[/tex]

2. Relevant equations

[tex]u=sin(z)\longrightarrow\space\,du=cos(z)dz[/tex]

3. The attempt at a solution

After making the substitution and simplifying I got the[tex]\displaystyle \int_a^b g(u)\,du[/tex] where:

g(u) =[tex]\frac{1}{u^9}[/tex]

a =1

b = .5

Then I do [tex]\displaystyle\int_{.5}^{1}\frac{1}{u^9}\,du\longrightarrow\frac{-1}{8sin(z)^8}[/tex]

I evaluated that on the interval [.5,1] but I got wrong answer, I know I went wrong somewhere.

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# Homework Help: Definite Intergral (subtuition)

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