Definition Of Logical Connectives

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Discussion Overview

The discussion revolves around the definitions of logical connectives, specifically the conditional statement represented as p → q. Participants explore the reasoning behind the truth values assigned to such statements, particularly in the context of discrete mathematics.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions whether the definition of the conditional statement p → q is based on reasoning or arbitrary choice, noting that it is false when p is true and q is false.
  • Another participant explains that by definition, if p is true, then q must also be true for the implication p → q to hold, suggesting that this aligns with logical reasoning.
  • A different perspective is presented, arguing that to disprove a statement of the form "If A then B," one must provide an example where A is true and B is false, emphasizing the importance of context in logical statements.
  • One participant uses an analogy involving a false mathematical statement to illustrate that any implication with a false antecedent is considered true, further complicating the understanding of logical implications.

Areas of Agreement / Disagreement

Participants express differing views on the nature of logical implications and the reasoning behind their definitions. There is no consensus on whether the definitions are arbitrary or based on logical reasoning.

Contextual Notes

Some participants highlight the potential confusion surrounding implications with false antecedents and the role of context in determining the truth of logical statements. The discussion does not resolve these complexities.

Bashyboy
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Hello,

I just began my Discrete Mathematics class. It is rather interesting, but I have a few questions regarding the definitions of logical connectives. For instance, my book states that the conditional statement,[itex]p \rightarrow q[/itex] serving as an example, is false when p is true and and q is false, and true otherwise.

Was there reasoning used to define this, or did the person arbitrarily define it?
 
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p→q is read "p implies q" or "if p then q"
That is, by definition, if p is true then so is q.

So if p were true, and q were not true then, p→q would not be a true statement.

Does that make sense?

We can go through a proof if you like.
 
Bashyboy said:
Was there reasoning used to define this, or did the person arbitrarily define it?

In mathematics (and perhaps in life) if someone claims "If A is true then B is true" and you wish to disprove it, then need an example when A is true and B is false. It doesn't help to cite an example when A is false. For example, if we claim if a figure is a triangle then the sum of it's interior angles is 180 deg. then we don't want to someone to disprove that by drawing a square.

If left to non-mathematicians ,when A is false, the statement "If A then B" might be declared to be "undecided" or something like that - something neither true nor false. But this doesn't work once you begin to consider logical functions with variables in them. To turn these into "statements" , you quantify the variables with modifiers like "for each" or "there exists". We regard the statement "For each x, if 0 < x < 3 then 0 < x^2 < 9" as true. We don't want to say it's "undecided" or false because of the case when x = 234. The "if..." part is rather like a filter. If a statement correctly filters out all cases that don't apply, then the statement is true.
 
Bashyboy said:
Hello,

I just began my Discrete Mathematics class. It is rather interesting, but I have a few questions regarding the definitions of logical connectives. For instance, my book states that the conditional statement,[itex]p \rightarrow q[/itex] serving as an example, is false when p is true and and q is false, and true otherwise.

Was there reasoning used to define this, or did the person arbitrarily define it?

If 2+2 = 5 then I'm the Pope. That's a true statement.

How could you disprove it? You'd have to show that

1) 2 + 2 = 5; and

2) I'm not the Pope.

But you can't do that! You can't show that 2 + 2 = 5 because that's false.

So you see, if 2 + 2 = 5 then I'm the Pope. Any implication where the antecedent is false, is a true implication.

Hope this helps. This is certainly a common area of confusion. After a while you'll get used to it. False antecedent implies anything.

By the way if I happened to be the Pope -- which, on an anonymous forum, can't be completely ruled out -- then "if 2 + 2 = 5 then I'm the Pope" is also a true implication. If the consequent is true, then the implication is true.

Therefore to make my examples work, I have to actually assure you that I am not the Pope :-) But if 2 + 2 were 5, I certainly would be.
 

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